Movie tickets and film streaming services are substitutes. If the price of film streaming increases, what happens in the market
for movie tickets? a. The supply curve shifts to the left. b. The supply curve shifts to the right. c. The demand curve shifts to the left. d. The demand curve shifts to the right.
1 answer:
Answer:
D. The demand curve shifts to the right.
Step-by-step explanation:
Movie tickets and film streaming services are substitutes, so an increase in the price of film streaming will cause an increase in the demand for movie tickets. Thus, at any given price, the demand curve of movie tickets shifts to the right, for example from demand A to demand B or demand C. as in the attached figure.
You might be interested in
Answer:
The real perimeter is:
And the area would be:
Step-by-step explanation:
For this case we know one side of a square given 6mm.
We can begin calculating the perimeter for the scale figure with this formula:
The area for this case is given by:
And we know that the drawing has a scale of 1 mm : 7 km and if we convert the perimeter to km we got:
And the area would be:
Define
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s