All categories

2 years ago

Which problem demonstrates the associative property of multiplication?

Mathematics

2 answers:

Ierofanga [76]2 years ago

7 0

Answer:

A (the first one)

Step-by-step explanation:

A demonstrates the associative property of multiplication.

max2010maxim [7]2 years ago

6 0

(5.2 • 3.1) • 1.9 = 5.2 • (3.1 • 1.9)

You might be interested in

Does x-4=5 has one solution

AfilCa [17]

Yes, if you do it correctly by following the Algebraic way you would get:

x-4=5
you need to find x.
you can do this by subtracting 4 from the x side and adding it to 5.
so it would be x= 5+4
then you jsut add 5 and 4 and you get x.
so x = 9.

7 0

3 years ago

Read 2 more answers

DON'T TROLL ME!!! I KNOW I'M GIVING A LOT OF POINTS BUT THAT DOESN'T MEAN YOU SHOULD TROLL AND TAKE THEM. HOW WOULD YOU FEEL IF

Likurg_2 [28]

Answer:

for me it was d=3.2t+0.6

Step-by-step explanation:

but to find the part where they intersect its (0.75,3)

6 0

3 years ago

Read 2 more answers

ANSWER IF YOU LOVE YOUR LORD!!!! Which graph represents the solution to: 2k+8<5k-1?

Leviafan [203]

Answer:

Third graph

Step-by-step explanation:

First, find the solution to the equation of inequality given.

2k + 8 < 5k - 1

Subtract 5k from both sides

2k + 8 - 5k < 5k - 1 - 5k

-3k + 8 < -1

Subtract 8 from both sides

-3k + 8 - 8 < -1 - 8

-3k < -9

Divide both sides by -3. (Note: < will change to > when dividing both sides with negative number)

$\frac{-3k}{-3}$ > $\frac{-9}{-3}$

k > 3

The graph that will represent this solution will show that all values of k are greater than 3. 3 is not included as a solution. The "o" on top of the 3 on the number line won't be shaded to indicate that 3 is not included. And also, the arrow will point from 3 towards our right.

Therefore, the 3rd graph is the answer.

3 0

3 years ago

Find the probability of each event.

jeka57 [31]

Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

The coin is fair, hence p = 0.5.

The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098$

$P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.001$

Hence:

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0098 + 0.001 = 0.0108$

0.0108 = 1.08% probability of the coin landing tails up at least nine times.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

5 0

2 years ago

Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti

Vikki [24]

Answer:

General Solution is $y=x^{3}+cx^{2}$ and the particular solution is $y=x^{3}-\frac{1}{2}x^{2}$

Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$

Thus the solution becomes

$\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+c$ $y=x^{3}+cx^{2$

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have $6=8+4c$

Thus solving for c we get c = -1/2

Thus particular solution becomes

$y=x^{3}-\frac{1}{2}x^{2}$

5 0

3 years ago