I think you meant to say the ratio of the areas (not perimeters). Also, HKO and FGO are not showing up, so it seems like a different problem. I'm going to answer the question you posted in the image attachments.
The triangle ABC has area 12 since
A = b*h/2 = 4*6/2 = 24/2 = 12
Triangle CEF has area 48 because
A = b*h/2 = 8*12/2 = 96/2 = 48
The ratio of the areas is found by dividing the area of ABC over the area of CEF (as the last box instructs) so we have 12/48 = 1/4
Therefore, the area of ABC is 1/4 that of the area of CEF
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In summary,
<h3>Answer for the first box: 12</h3><h3>Answer for the second box: 48</h3><h3>Answer for the third box: 1/4</h3>
Answer:
a square, rectangle,trapezoid
Step-by-step explanation:
The area would be about 83.14.
You can find this by starting with the formula for the area of an equilateral triangle:
A = 
In this equation, A is the area and S is the side. So we'll just plug in the value.
A =
A = 
A = 
A = 83.14
Change iny\change in x
change in y=4.4-2.2=2.2
change in x=11-5.5=5.5
slope=2.2\5.5=0.4
