Question

In △JKL, solve for x. (A)74.89 (B)30.29 (C)38.16 (D)66.73

Answer 1

ANSWER

(C)38.16

EXPLANATION

The acute angle given in the right triangle is 27°.

The side length adjacent to the 27° angle is 34 units.

The side length we want to find is x units, which is the hypotenuse of the right triangle.

We use the cosine ratio to obtain:

$\cos(27 \degree) = \frac{adjacent}{hypotenuse}$

$\cos(27 \degree) = \frac{34}{x}$

Solve for x,

$x = \frac{34}{\cos(27 \degree)}$

$x = 38.16$

to the nearest hundredth.

Answer 2

Answer:

The correct answer is option C.  38.16

Step-by-step explanation:

Points to remember

Trigonometric ratios

Sin θ  = Opposite side/Hypotenuse

Cos θ = Adjacent side/Hypotenuse

Tan θ = Opposite side/Adjacent side

To find the value of x

From the figure we can see a right angled triangle. △JKL

Cos 27 = Adjacent side/Hypotenuse

 = KL/JL

 = 34/x

x = 34 / Cos 27

 = 34 / 0.891

 = 38.16

Therefore the correct answer is option C.  38.16