If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
Answer:
y = 30x + 20
Step-by-step explanation:
y = mx + b
find b
b=20
find m
m=30
<em>5</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>your</em><em> </em><em>answer</em><em> </em><em>of</em><em> </em><em>this</em><em> </em><em>question</em><em> </em>
F(x) = 5x - 2
f(-3/5) = 5(-3/5) - 2
f(-3/5) = -15/5 - 2
f(-3/5) = -3 - 2
f(-3/5) = -5
The y intercept of given equation y = 2x + 10 is (0, 10)
<em><u>Solution:</u></em>
Given equation of line is:
y = 2x + 10
<em><u>To find: y intercept of the line</u></em>
The point where a line or curve crosses the y-axis of a graph is y intercept
<em><u>Finding y - intercept:</u></em>
To find the y-intercept, plug 0 in for 'x' and solve for 'y'
<em><u>Substitute x = 0 in given equation</u></em>
y = 2(0) + 10
y = 0 + 10
y = 10
Thus the y intercept of given equation is (0, 10)
