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4 years ago

Six more than the quotient of a number and 9 equals 2

Mathematics

1 answer:

patriot [66]4 years ago

5 0

Answer:

-36

Step-by-step explanation:

Express it in an equation:

6+(x/9)=2

-6 -6

x/9=-4

-36

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Various problems with data collection can cause some observations to be missing. Suppose a data set has 20 cases. Here are the v

mr Goodwill [35]

Answer:

a) Mean= 15, standard deviation= 5.1575

b) Mean= 15, standard deviation= 3.6469

c) See below

Step-by-step explanation:

(a) Compute the mean and standard deviation for the 10 cases for which x is not missing.

The mean using the ten known values is

$\bar x=\frac{17+6+12+14+20+23+9+12+16+21}{10}=15$

The standard deviation is

$\small s=\sqrt{\frac{(17-15)^2+(6-15)^2+(12-15)^2+(14-15)^2+(20-15)^2+(23-15)^2+(9-15)^2+(12-15)^2+(16-15)^2+(21-15)^2}{10}}=5.1575$

(b) Create a new data set with 20 cases by using imputation where you set the values for the 10 missing cases equal to the mean that you computed in the previous part. Compute the mean and standard deviation for this new data set with 20 cases.

The new data set would be

17, 6, 12, 14, 20, 23, 9, 12, 16, 21, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15

The new mean for this set of values would be then

$\bar x=\frac{\displaystyle\sum_{i=1}^{20}x_i}{20}=15$

The new standard deviation is now

$s=\sqrt{\frac{\displaystyle\sum_{i=1}^{20}(x_i-\bar x)^2}{20}}=3.6469$

(c) Summarize what you have learned about the possible effects of this type of imputation on the mean and the standard deviation.

Obviously, this way of imputation is somewhat arbitrary and will produce a set of data undoubtedly skewed.

It could possibly be a sensible way of imputing data if the amount of missing data is very little compared to the whole set, for example one or two data in a set of 100, but in this case we have 50% of missing data and it makes no sense this procedure.

4 0

3 years ago

Help me asap please!! I'll give brainliest

miskamm [114]

Answer:

first one

Step-by-step explanation:

8 0

3 years ago

This is a System Of Equations and I'd like it to get solved by the Elimination or Substitution Method.x+2y=83x+5y=8

Sonbull [250]

Answer:

x=133 y=-25

Step-by-step explanation:

I'll do both ways for you. So let's start with Substitution:

With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.

x + 2y = 83 & x + 5y = 8

Solve for x.

x = 83 - 2y & x = 8 - 5y

Once you have solved for x, set each equation equal to one another and solve for y now.

83 - 2y = 8 - 5y

Isolate all variables to one side:

83 = 8 - 3y

Now subtract the 8 to fully isolate the y variable:

75 = -3y

Divide by -3:

-25 = y Now that you have your first variable, plug it into one of the original equations and solve for x.

x + 2(-25) = 83

x - 50 = 83

x = 133

Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:

Put each equation on top of one another and subtract:

x + 2y = 83

- (x + 5y = 8)

The x's will cancel out:

(x - x) + (2y - 5y) = (83 - 8)

Simplify:

-3y = 75

Solve for y

y = -25

Then, plug y = -25 into one of the original equations:

x + 5(-25) = 8

Solve for x:

x - 125 = 8

x = 133

Hope this helps!

8 0

3 years ago

Help please! I've never been good at percents

Igoryamba

Answer:

the answer is: 64.9 but I'm not sure

5 0

3 years ago

Enter what that means? <br> Help someone.

Luda [366]

$\frac{x^2}{3}$ is the same as $\frac{1}{3}x^2$

Dividing by 3 is the same as multiplying by the fraction 1/3

7 0

4 years ago