The Large Counts Condition must be met so that the sampling distribution of a sample proportion is approximately normal. Using a ppropriate notation, write out the Large Counts Condition for Normality.
1 answer:
Answer:
np>10 and n(1-p)>10
Step-by-step explanation:
Appropriate notation the Large Counts Condition for Normality is The Large Counts Condition for Normality states that is the number of successes and failures which should be above the 10 to be assume normality that is here express as n(p)>10 and n(1-p)>10 This is the notation of the Large Counts Condition for Normality.
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The answer is A) because 98% of 300 is 294 and 1% of 300 is 3; first just divide 294 by 98% (.98) and u get 300 then multiply 300 by 1% (.01) and u get 3
