All categories

3 years ago

PLS HELP TELL WHETHER X AND Y SHOW DIRECT VARIATION!!!

Mathematics

1 answer:

jarptica [38.1K]3 years ago

4 0

Answer:

Try using this calculator

Step-by-step explanation:

https://www.mathpapa.com/algebra-calculator.html

You might be interested in

Which of the following is the solution for the inequality below? -3x+2<8

Zepler [3.9K]

Answer:

x>-2

Step-by-step explanation:

First you have to subtract 2 from both sides, which leaves you with -3x=6, then you have to divide -3 on both sides to get the variable by itself. Which is x<-2, but you have to switch the sign because you multiplied/divided by a negative number, then you get left with x>-2........Hope that helped!!!!!!!!!!:)

7 0

2 years ago

Theresa has $12 in nickels amd quarters if she has the same number of each kind of coin how many nickels and quarters does she h

Bogdan [553]

n=# of nickels

q=# of quarters

$12 is 1200 cents

5n+25q=1200

n=q

substitute q for n or n for q

5q+25q=1200

30q=1200

q=1200/30

q=40 quarters and therefore n=40 nickels

40 quarters is $10 and 40 nickels is $2, therefore you have $12

Hope this helps.

4 0

3 years ago

Can someone explain 7 -10, my teacher does one problem and hands worksheets out :/

Kitty [74]

Answer:

can you please identify the crossed out ones?

6 0

3 years ago

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative. f"(x) = 2x + 9e

ad-work [718]

Answer:

$f(x)=\frac{x^3}{3}+9e^x+Cx+D$

Step-by-step explanation:

The function F(x) is an antiderivative of the function f(x) on an interval I if

F′(x) = f(x) for all x in I.

The function F(x) + C is the General Antiderivative of the function f(x) on an interval I if F′(x) = f(x) for all x in I and C is an arbitrary constant.

The Indefinite Integral of f(x) is the General Antiderivative of f(x).

$\int {f(x)} \, dx =F(x)+C$

To find the first antiderivative you must integrate the function $f''(x) = 2x + 9e^x$

$f'(x)=\int { 2x + 9e^x} \, dx \\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:2xdx+\int \:9e^xdx = x^2+9e^x\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\x^2+9e^x+C$

To find the second antiderivative you must integrate the function $f'(x) =x^2+9e^x+C$

$f(x)=\int {x^2+9e^x+C} \, dx\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:x^2dx+\int \:9e^xdx+\int \:Cdx= \frac{x^3}{3}+9e^x+Cx\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\\frac{x^3}{3}+9e^x+Cx+D$

Therefore,

$f(x)=\frac{x^3}{3}+9e^x+Cx+D$

8 0

3 years ago

Which of the following expressions is equivalent to the one shown below? (-5 x 4)3

salantis [7]

Answer:

-60

Step-by-step explanation:

We'd solve anything inside the parentheses first:

-5 * 4 = -20

Now multiply:

-20 * 3 = -60

Our answer would be -60

5 0

3 years ago

Read 2 more answers