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ElenaW [278]
3 years ago
7

Three shipping companies want to compare the mean numbers of deliveries their drivers complete in a day.

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

#1 is 10

# 2 is

6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The (Mean) = 10

(6- 10) + (7- 10) + (8- 10) + (9- 10) + (10- 10) + (10- 10) + (10- 10) + (12- 10) + (14- 10)

4 + 3 + 2 + 1 + 0 + 0 + 0 + 2 + 4

= 16/10 = 1 6/10

The (MAD) = 1 6/10

#3 Groups A & B

#4 sorry I can’t figure this out but I did 1/2/3

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Sergio [31]

Answer:

1/3 i think this will the answer

4 0
4 years ago
Read 2 more answers
On Monday, Sean bought 3 cookies and 5 cakes and spent $78.75. On Tuesday, Sean bought 8 cookies and 2 cakes and spent $40.
andreyandreev [35.5K]

Answer:

1 cookie = $1.25    1 cake = $15

Step-by-step explanation:

set up a system of equations:

let x = 1 cookie

let y = 1 cake

3x + 5y = 78.75

8x + 2y = 40

I multiplied the first equation by 2 to get:  6x + 10y = 157.50

I multiplied the second equation by -5 to get:  -40x - 10y = -200.00

If you add both equations, the y-terms will be eliminated

-34x = -42.50

x = 1.25

Plug in 1.25 into equation to find value of y:  8(1.25) + 2y = 40

                                                                           10 + 2y = 40

                                                                            2y = 30

                                                                             y = 15

6 0
3 years ago
Пожалуйста,очень нужны 4,5,6<br> Срочнооооооо<br> Спасибо заранее
kifflom [539]
B. is the answer to your question!! Hope this helps!! :D
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4 years ago
Need help... post question in comments once someone answers
Ksenya-84 [330]

What's up? How can I help?


3 0
3 years ago
What is the equation of the line that passes through the points (-3,5) (6,8)
Ratling [72]

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

6 0
2 years ago
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