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laiz [17]
2 years ago
10

How are 2-D and 3-D objects related to each other in real world​

Mathematics
1 answer:
stich3 [128]2 years ago
8 0

Answer:

You can see 2-D flat shapes on the faces of 3-D objects.

For example: You go to the store and you see a box,

the box has 6 faces. The bottom of the box is one of It's faces which is 2-D.

Step-by-step explanation:

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Charlie watched 1 3 of a movie in the morning, and he watched some more at night. By the end of the day, he still had 2 5 of the
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Answer: 4/15 of the movie

Step-by-step explanation:

In the morning, Charlie watched ¹/₃ of a movie. He then watched some more at night.

At the end of the day, he still had ²/₅ of the movie to watch.

The proportions of an item must always add up to one. This means that if you added the 1/3 to the 2/5 and then to the fraction Charlie watch at night, they should add up to one.

¹/₃ + ²/₅ + x = 1

x = 1 - ¹/₃ - ²/₅

x = \frac{15 - 5 - 6 }{15} \\\\x = \frac{4}{15}

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2 years ago
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
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Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
3 years ago
Please help number 20
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Shashi Rimoko earns $620 per week as a chef. He has group
finlep [7]

Out of the weekly amount that Shashi Rimoko makes, a deduction of $37.93 is made for insurance.

The total Medical cost is $9,560 and out of this, the amount paid by Shashi per year is:

<em>= Amount x (1 - percentage paid by restaurant)</em>

= 9,560 x ( 1 - 80%)

= $1,912

The amount he pays for Dental coverage is:

<em>= Amount x (1 - percentage paid by restaurant)</em>

= 172 x (1 - 65%)

= $60.20

The total amount he pays for insurance per year is:

<em>= Medical + Dental </em>

= 1,912 + 60.20

= $1,972.20

The weekly deduction is:

<em>= Year amount / No. of weeks in year </em>

= 1,972.20 / 52

= $37.93

In conclusion, $37.93 is deducted from his paycheck every week.

<em>Find out more at brainly.com/question/16711490.</em>

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