How do you find the length of a tangent with the length of a secant?

1 answer:

3 0

Answer: How do you find the length of a tangent segment? Formula : If a secant and a tangent of a circle are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment .

Step-by-step explanation:

hope it helps you.

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Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?

Alexeev081 [22]

Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer

the first one is the answer

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3 years ago

A plumber charges $25 for a service call plus $50 per hour of service. Write an equation in slope-intercept form for the cost, C

Alex787 [66]

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The diagonals of this rhombus are 8 and 16 units long. Their intersection creates four right angles, two 4-unit-long segments, a

Roman55 [17]

Answer:

$64\ \text{sq. units}$

Step-by-step explanation:

Area of a rhombus is the product of the length of the diagonals divided by two.

Length of one diagonal is 8 units and the other diagonal is 16 units

Area is given by

$A=\dfrac{8\times 16}{2}\\\Rightarrow A=64\ \text{sq. units}$

The area of the rhombus is $64\ \text{sq. units}$

Another approach is the diagonals have created 4 triangles where the base and is height is either 4 units long or 8 units long so the area of the rhombus would be the area of the 4 triangles.

$A=4\times \dfrac{1}{2}\times 4\times 8\\\Rightarrow A=64\ \text{sq. units}$