frank has two same size rectangles divided into the same number of equal parts. one rectangle has 3/4 of the parts shaded, and t
he other has 1/3 of the parts shaded. Part A into how many parts could each rectangles be divided? show your work by drawing the parts of each rectangle Part B is there more than one possible answer to part A? if so, did you find the least number of parts into which both rectangles could be divided, explain your reasoning.
I believe the most logical answer would be is to divide so us the kcf method keep change flip so 5 stays the same then change division into multiplication then flip the fraction 1/3 into 3/1 so now we have 5 times 3 is 15
To solve questions of these sorts, bring all the terms to one side & simplify it leaving x alone in the other side of the equation (other side of the equal to sign). After simplification you'll get the value of x.
Remember that the signs & operations will change when you bring a term to the other side of the equation.
So, addition will become subtraction, subtraction will become addition, multiplication will become division & division will become multiplication.