For
ax^2+bx+c=0
discriminatn is b^2-4ac
a=4
b=12
c=9
discriinat is
12^2-4(4)(9)=
144-144
0
the discrminat is 0
My teacher does the factor tree which is this
75
↑ ↑
15 5
↑ ↑
2 5
So that would be 2 * 5 * 5 or 2 * 5²
Answer:
B -6x+35=-6x+35
Step-by-step explanation:
Let's analyze the options:
A ........................
- 6x+35=-6x-35
- 6x + 6x = -35 - 35
- 12x = - 70
- x = -70/12
This one has one solution
B ........................
- -6x+35=-6x+35
- - 6x + 6x = 35 -35
- 0 = 0
This one has infinitely many solutions as results in true equation for any value of x
C ........................
- 6x+35=-6x+35
-
6x + 6x = 35 -35
- 12x = 0
- x = 0
This one has one solution
D ........................
- -6x+35=-6x-35
- -6x +6x = - 35 - 35
- 0 = -70
This one has no solutions as results in false equation for any value of x
You can make 128 different couches because 16x8=128
Distributive property goes like this:
a(b+c)=ab+ac
10.
I'll distribute each seperatly then group
2(x+3)=2(x)+2(3)=2x+6
4(x-2)=4(x)+4(-2)=4x-8
2x+6+4x-8=6x-2
11.
4(3x²-1)=4(3x²)+4(-1)=12x²-4
5(2x+2)=5(2x)+5(2)=10x+10
12x²-4+10x+10=12x²+10x+6
12.
4(2x-8)=4(2x)+4(-8)=8x-32
-(x-4)=-1(x-4)=-1(x)-1(-4)=-x+4
8x-32-x+4=7x-28