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Feliz [49]
3 years ago
6

Please help the last question of the day! For brainliest

Mathematics
1 answer:
Semenov [28]3 years ago
8 0

Answer:

2\10

Step-by-step explanation:

1\2 = 5\10

7\10 - 2\10 = 5\10

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What is a shape that has two parallel, congruent circular bases.
Veronika [31]

Answer:

prism

Step-by-step explanation:

7 0
4 years ago
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Find the missing side lengths, leave your answers as radical in simplest form. ( Please answer ASAP!)
alexira [117]

Answer:

9) a = 8, b = 4√2

10) x = 7√2, y = 7

11) x = 5√2, y = 5

12) a = 10, b = 5√2

Step-by-step explanation:

You can notice all these triangles are special as 45° - 45° - 90° triangles. In 45° - 45° - 90° triangles, the hypotenuse is √2 times the sides. We can set up these equations and solve:

9)

a = 4√2 * √2

a = 8

Since the triangle is isosceles, the legs are the same length, so:

b = 4√2

10)

x = 7 * √2

x = 7√2

Since the triangle is isosceles, the legs are the same length, so:

y = 7

11)

x = 5 * √2

x = 5√2

Since the triangle is isosceles, the legs are the same length, so:

y = 5

12)

a = 5√2 * √2

a = 10

Since the triangle is isosceles, the legs are the same length, so:

b = 5√2

8 0
3 years ago
(-18x^2+12x-2)*(x^3+12x^2+48x+64)
prohojiy [21]
<h2>Answer:</h2>

-18x^5-204x^4-722x^3-600x^2+672x-128

<h2>Explanation:</h2>

( - 18 {x}^{2}  + 12x - 2)

( {x}^{3}  + 12 {x}^{2}  + 48x + 64)

There are multiple ways to solve this for example the foil method or the box method. I prefer to do the box method.

First we are going to set it up

After we set it up we have to solve it so first we are going to multiply

{x}^{3}  \times  - 18 {x}^{2}  =  - 18 {x}^{5}

We have to add the exponent

- 18 {x}^{2}  \times 12 {x}^{2}  =  - 216 {x}^{4}

- 18 {x}^{2}  \times 48x =  - 864 {x}^{3 }  \\  - 18{x}^{2}  \times 64 =  - 1152 {x}^{2}  \\ 12x \times  {x}^{3}  = 12 {x}^{4}  \\ 12x \times 12 {x}^{2}  = 144 {x}^{3}

12x \times 48x = 576 {x}^{2}  \\ 12x \times 64 = 768x

- 2  \times  {x}^{3}  =  - 2 {x}^{3}  \\  - 2 \times 12 {x}^{2}  =  - 24 {x}^{2}  \\  - 2 \times 48x =  - 96x \\  - 2 \times 64 =  - 128

Now we have to add them

-18x^5 stays because there is nothing to add to

Now we add the rest

-216 {x}^{4}  + 12 {x}^{4}  =  - 204 {x}^{4}

- 864 {x}^{3}  + 144 {x}^{3}  +  - 2 {x}^{3}  = -  722 {x}^{3}

768x - 96x = 672x

And -128 stays the same

- 1152 {x}^{2}  + 576 {x}^{2}  - 24 {x}^{2}  =  - 600 {x}^{2}

The answer is

-18x^5-204x^4-722x^3-600x^2+672x-128

5 0
4 years ago
The counting numbers are also called Integers
melisa1 [442]

Answer: Yes

Step-by-step explanation:

What is your question

8 0
3 years ago
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1 1/3 x 1/14<br> Help please
nikklg [1K]

Step-by-step explanation:

=11/3×1/14

=3.67×0.07

=0.2568

7 0
3 years ago
Read 2 more answers
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