Answer:
Step-by-step explanation:
230.86/23.8= and you'll have your answer (I don't have a calculator on me sorry)
Answer:
4
Step-by-step explanation:
set
constrain:
Partial derivatives:
Lagrange multiplier:
![\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%3Da%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2x%5C%5C2y%5Cend%7Barray%7D%5Cright%5D%2Bb%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3x%5E2%5C%5C3y%5E2%5Cend%7Barray%7D%5Cright%5D)
4 equations:
By solving:
Second mathod:
Solve for x^2+y^2 = 7, x^3+y^3=10 first:
The maximum is 4
Answer:
(A) h(x) = 1/4x -2
Step-by-step explanation:
Given: f(x)=4x+8
Rewrite with y: y=4x+8
Switch x and y: x=4y+8
Solve for y: x-8=4y
(x-8)/4=y
1/4x-2=y
y=1/4x-2
This means that h(x) = 1/4x -2 is the correct answer
Answer:
56
Step-by-step explanation:
area of whole figure=
l×b
=20×10
=200
also,area of small fig.
=l×b
=18×8
=144
thus area of shaded part =a of whole- a of small
=200-144
=56
