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Oduvanchick [21]

3 years ago

11

A computer is used to generate passwords. Passwords are made up of numbers from 1–8 and lowercase letters. The computer generate

s passwords one character at a time. What is the probability the first character is an even number? Enter your answer, as a decimal rounded to the nearest hundredth, in the box.

1 answer:

Snezhnost [94]3 years ago

4 0

4/8 simplified to 1/2 because out of eight there are 4 even and 4 odd numbers 0.50

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3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a <em>normal distribution </em>with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago

Paul biked 55 miles in 10 hours . what is the unit rate of miles per hour

irinina [24]

Answer:

5.5 miles per hour

Step-by-step explanation:

Since he travels a total of 55 miles in 10 hours, you need to divide.

55/10 = 5.5

total hours/total miles = miles per hour

3 0

3 years ago

Read 2 more answers

Bobby hopes that he will someday be more than 70 inches tall. he is currently 61 inches tall. how many more inches,

Dominik [7]

Bobby should grow an amount greater than 70-61 = 9 inches to become taller than 70 inches. Therefore, the correct answer is that Bobby must grow an amount of x> 9 inches to be taller than 70 inches.

4 0

3 years ago

5. 6.9Write the decimal as a a fraction or mixed number?

salantis [7]

6.9 as a fraction or mixed number

6.9 = 6 9/10

This is also the same as 69/10

5 0

1 year ago

-(-4)(-6)-3/5(10+15)/1/3

Ksenya-84 [330]

Answer:

$-29$

solving steps:

$\sf \hookrightarrow -\left(-4\right)\left(-6\right)-3/5\left(10+15\right)/1/3$

$\sf \hookrightarrow -\left(-4\right)\left(-6\right)-3/5\cdot \:25/1/3$

$\sf \hookrightarrow -24-3/5\cdot \:25/1/3$

$\sf \hookrightarrow -24-5$

$\sf \hookrightarrow -29$

3 0

2 years ago

Read 2 more answers