Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

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The angles represented by the expressions (2x+46) and (3x-6) are complementary angles. find the measure of the larger angle. Im

ivolga24 [154]

Answer:

Step-by-step explanation:

complimentary angles add up to 90 so:

3x-6 + 2x +46 = 90

5x +40 = 90

5x = 50

x = 10

2(10)+46 = 66

3(10) - 6 = 24

8 0

2 years ago

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Find the solution to t - (-2) = 6.

Alex_Xolod [135]

t - (-2) = 6
t + 2 = 6
subtract 2 to both sides
t + 2 - 2 = 6 -2
simplify
t = 4

6 0

2 years ago

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