I believe the answer is B because you multiply 18 and 40 then subtract 320 from that and you will 400.
Answer:
Step-by-step explanation:
the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.
They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.
We should recall:
diameter = 2 times the radius circumference of a cirlce = 2π r
How do we find the diameter of the of the semi circle?
The perimeter of the semi circle is given as 108 cm
Perimeter of the semicirle = 2r + π r diameter plus semi circumference
108 = r ( 2 + π) factor out the r and solve for r
108 / (2 + π) = r divide both sides by ( 2 + r)
Now we know r, the perimeter of the squqre is 4 times 2r or 8r
perimeter of square = 8 [ 108 / (2 + π) ] π I used 3.14
= 864 / 5.14
= 168.1 cm I got rounded to nearest tenth
<em>When I re-checked by work I found a few math, logic and calculation errors. Please re-check my answer for any more mistakes.</em>
Answer:
12 dollars
Step-by-step explanation:
<h3>Lona should have 12 dollars because it says that it is <em>2 1/3</em> as much as Mary-Anns amount. You would divide 28➗2 1/3=12</h3><h3 /><h3>hope this helps</h3>
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
