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Wewaii [24]
3 years ago
11

Henry would receive $8 per hour, His total earnings amount was $1,920. How many hours did henry work for?

Mathematics
1 answer:
enot [183]3 years ago
6 0

Answer: 240

Step-by-step explanation: 1920/8

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Company A makes a large shipment to Company B. Company B can reject the shipment if they can conclude that the proportion of def
boyakko [2]

Answer:

z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17  

The p value for this case would be given by:

p_v =P(z>3.17)=0.00076  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

Step-by-step explanation:

Information provided

n=400 represent the random sample taken

X=59 represent number of defectives from the company B

\hat p=\frac{59}{400}=0.1475 estimated proportion of defectives from the company B  

p_o=0.1 is the value to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true proportion of defectives is higher than 0.1 then the system of hypothesis are.:  

Null hypothesis:p \leq 0.1  

Alternative hypothesis:p > 0.1  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17  

The p value for this case would be given by:

p_v =P(z>3.17)=0.00076  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

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