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professor190 [17]
3 years ago
14

PLEASE HURRY!!!!!!

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Expand the binomial:

(√2/5 + 5/2 <em>i</em> )² = (√2/5)² + 2<em>i</em> (√2/5) (5/2) + (5/2 <em>i</em> )²

… = 2/25 + √2 <em>i</em> + 25/4 <em>i</em> ²

… = -617/100 + √2 <em>i</em>

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Which statements can be used to compare the characteristics of the functions? Select three options.
kakasveta [241]

Answer:

Option B and D

Step-by-step explanation:

The complete question is attached

Solution

All f(x) values are not negative hence, option A is incorrect

All g(x) values are the greatest among the three f(x), g(x) and h (x), hence option B is correct

The range of all three functions is different. Hence, option C is incorrect

All h (x) values are negative. Hence, Option D is correct

6 0
3 years ago
PLS HELP me ASAP FOR 11 (SHOW WORK!!)
Elodia [21]
2.5/0.2=12.5
2.5 times 12.5=31.25
The actual height of the building is 31.25 cm
7 0
3 years ago
Read 2 more answers
A dripping faucet leaps 1.8 ounces per minute. How many ounces leak in 30 minutes?
zzz [600]

Answer:

54 ounces

Step-by-step explanation:

1.8 * 30 = 54

5 0
3 years ago
Calculate the total surface area of a cuboid with the following dimensions. 4m by 6m by 8m​
bonufazy [111]

Answer:

V = 192 m^3

Step-by-step explanation:

The volume of a cuboid is given by

V = l*w*h

V = 4m * 6m *8m

V = 192 m^3

6 0
3 years ago
One-fourth of the residents of a particular community leave their garage doors unlocked when they go out to do an errand. The lo
Inessa [10]

Answer:

Required Probability = 0.625

Step-by-step explanation:

Given,

Probability of unlocked doors, P(U) = 0.25

Probability of locked doors, P(U') = 0.75

Probability of something being stolen when door is unlocked, P(S/U) = 0.05

Probability of something not being stolen when door is unlocked, P(S'/U) = 0.95

Probability of something being stolen when door is locked, P(S/U') = 0.01

Probability of something not being stolen when door is locked, P(S'/U') = 0.99\

probability of being stolen either door is locked or not,

P(S) =P(S/U).P(U) + P(S\U').P(U')

       = 0.05 x 0.25 + 0.95 x 0.75

       = 0.0125 + 0.0075

       = 0.02

Probability that door was unlocked when while steeling can by given by

P(U/S)\ =\ \dfrac{P(S/U).P(U)}{P(S)}

            =\ \dfrac{0.05\times 0.25}{0.02}

            = 0.625

hence, the required probability is 0.625.  

7 0
3 years ago
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