<h2>
Answer:</h2><h2>
The probability that Roy gives randomly an SUV = 15 / 47</h2>
Step-by-step explanation:
The total number of used cars owned by Roy = 47
[12 trucks + 20 cars + 15 SUV = 47 cars]
The total number in sample space, n (S) = 47
The probability that Roy is giving away and SUV = ?
Let A be the event that Roy is giving an SUV
Total no of SUV's , n (A) = 15
The probability of giving an SUV, P (A) = n (A) / n (S)
P (A) = 15 / 47
Answer:
Percent chance of winning = A / (A +B) = 1 / (1 +6) * 100 = 14.29 %
Step-by-step explanation:
Answer:
q
Step-by-step explanation:
