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4 years ago

If m1 = 31° and m2 = 94°, what is m3?

Mathematics

1 answer:

IgorLugansk [536]4 years ago

8 0

Answer:

Step-by-step explanation:

bc m1=31 and m2=29 you subtract 31-29and it is 27

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PLEASE HELP its about integers

Anastaziya [24]

Consecutive even integers are 2 apart (2,4,6)
they are
x,x+2,x+4

the sum is 126

x+x+2+x+4=126
3x+6=126
minus 6 from both sides
3x=120
divide both sides by 3
x=40

x+4 is biggest
40+4=44

biggest integer is 44

3 0

3 years ago

Cierra has three more than 1/2 as many purses as Asia defined a variable and write an expression to represent the number of purs

Ray Of Light [21]

Answer:

The equation representing the number of purses Ceirra has is $c=3+\frac{1}{2}\times a$ .

Ceirra has 9 purses in her collection.

Step-by-step explanation:

Given,

Cierra has three more than 1/2 as many purses as Asia.

Solution,

Let the number of purses Cierra has be 'c'.

And also the number of purses Asia has be 'a'.

Now according to question, Cierra has 3 more than 1/2 purses as Asia has.

Framing in equation form, we get;

$c=3+\frac{1}{2}\times a$

Hence The equation representing the number of purses Ceirra has is $c=3+\frac{1}{2}\times a$ .

Now we solve the equation;

Since Asia has 12 purses.

So we substitute the value of 'a', and get;

$c=3+\frac{1}{2}\times12=3+6=9$

Hence Ceirra has 9 purses in her collection.

6 0

3 years ago

What is 6/15 as a decimal

Thepotemich [5.8K]

$\frac{6}{15} = \frac{2\times 3}{5\times 3} = \frac{2}{5} = 0.4$

7 0

4 years ago

Please I really need help on this matter question

Katarina [22]

The answer should be 1. Keep in mind that all cubic curves will always have at least 1 real zero. The embedded image is a graph of y=(x+8)³+9

The second answer should be y=x $x^{4}$ -6x $x^{3}$ +6x $x^{2}$ -6x+5 (the last answer choice), as seen by the second image.

6 0

4 years ago

Read 2 more answers

A seller has acquired 120 randomly selected items from a vendor for his stores. He has an allowance of 10% for damaged items. Of

wariber [46]

Answer:

Step-by-step explanation:

Given that a seller has acquired 120 randomly selected items from a vendor for his stores. He has an allowance of 10% for damaged items. Of the 120 items acquired from the vendor, the seller found that 15 are damaged.

Population proportion= 0.10

Sample proportion = 15/120 = 0.125

To test whether the population proportion of the vendor's items exceeds the seller's allowable limit,

the hypotheses would be

$H_0: p = 0.10\\H_a: p >0.10$

(right tailed test)

7 0

4 years ago