Answer:
x = 3 + √6 ; x = 3 - √6 ;
; 
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:

for the equation ax² + bx + c = 0
thus,
the roots are

or

or
and, x = 
or
and, x = 
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are

or

or
and, x = 
or
and, x = 
or
and, x = 
or
and, 
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ;
; 
<span>y" + 9y = 0
m^2 + 9 = 0
m = ± 3i
yH = C1 cos 3t + C2 sin 3t
yP = C3 t sin 3t + C4 t cos 3t
hope this helps </span>
(x² - 3x + 7) + (3x² + 5x - 9)
(x² + 3x²) + (-3x + 5x) + (7 - 9)
4x² + 2x - 2
Answer:
-2
Step-by-step explanation:
I mean i use the slope formula
and you just plug in the values of the coordinates.
88(3.7+4.3)-2*2.6
88(8)-2*2.6
704-2*2.6
704-5.2
698.8
I hope it helps!
Please mark Brainliest if it does!:-)