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AfilCa [17]
3 years ago
5

Solve 5c − c + 10 = 34

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0
Your answer would be c=6

step1: <span>Simplify </span><span>5c-c+10<span>5c−c+10</span></span><span> to </span><span>4c+10<span>4c+1<span>0
</span></span></span><span><span>4c+10=34</span>
</span>step2: <span>Subtract </span><span>10</span> from both sides
<span>4c=34−10

step 3: </span>Simplify 34-1034−10 to 24
4c=24<span>
step 4: divide both sides by 4
c=24/4

step 5: simplify 24/4 to 6

Answer:
c=6
</span>
PtichkaEL [24]3 years ago
5 0
Let's solve your equation step-by-step.

<span><span><span><span>5c</span>−c</span>+10</span>=34

</span>Step 1: Simplify both sides of the equation.

<span><span><span><span>5c</span>−c</span>+10</span>=34

</span><span>Simplify: (Show steps)

</span><span><span><span>4c</span>+10</span>=34

</span>Step 2: Subtract 10 from both sides.

<span><span><span><span>4c</span>+10</span>−10</span>=<span>34−10

</span></span><span><span>4c</span>=24

</span>Step 3: Divide both sides by 4.

<span><span><span>4c/</span>4</span>=<span>24/4

</span></span><span>c=6

</span>Answer:

<span>c=<span>6</span></span>
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Step-by-step explanation:

Let x= Number of sessions.

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When both plan charges the same, then

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3 years ago
A net force of 24 N is acting on a 4.0-kg object. Find the acceleration in m/s 6m/s^2
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Step-by-step explanation:

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the net force exerted on it=F=24N=kgm/s²

the acceleration of the object=a=?

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8 0
3 years ago
Anything helps ! Brainilest to right answer only .!
Alex_Xolod [135]

x = -16 or x = 5

Solution:

Given polynomial:

x^{2}+11 x-80=0

To find the roots of the polynomial.

Split the middle term 11x.

11x = 16x - 5x

x^{2}+11 x-80=0

x^{2}+16x-5x-80=0

(x^{2}+16x)+(-5x-80)=0

Take the x common in first 2 terms an -5 common in next 2 terms.

x(x+16)-5(x+16)=0

Take (x + 16) common in both terms.

(x+16)(x-5)=0

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Answer:

<em>If you are asking if that's correct then yes it is</em>

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Hope this Helps :)

6 0
3 years ago
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