Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
c = 4
Step-by-step explanation:
5/10 simplifies to 1/2
what over 8 simplifies to 1/2? 4/8 does
so c = 4
Answer:
The southwest corner of the garden will be 2 feet south and 3 feet west of the tree. A circle has a center at (3,5). What is the area of the circle to the nearest tenth of a square unit? Which of the following could be the vertices of the triangle? A garden that is 5 feet by 6 feet has a walkway that is 2 feet wide around it.
What do u want to find the domain and range of?
X= 13, The answer is 31/35
Your welcome