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3 years ago

PLEASE HELP ME!! I GAVE ALL MY POINTS! EXPLAIN IF POSSIBLE

Mathematics

1 answer:

SpyIntel [72]3 years ago

3 0

Answer:

10 mice left after 5 years

Step-by-step explanation:

The function is given:

f(x) = 5719(0.28)ˣ
f(x) is the number of mice left after x years, 5719 is initial number of mice (now) and x is the number of years from now

Substitute x with 5 for 5 years and find the value of the function.

f(5) = 5719(0.28)⁵ = 10 (rounded up to the integer number)
Multiply 5719 by 0.28 to the 5th power to get approximate number of 10

There will be 10 mice left after 5 years

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If f(x) = x3 – 2x2, which expression is equivalent to f(i)?

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d) 2 – i

Explanation

f(x) = x³ – 2x²

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Let’s play Pick-A-Ball with replacement! There are 10 colored balls: 3 red, 4 white, and 3 blue. The balls have been placed into

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Answer:

0.48

Step-by-step explanation:

There are 10 colored balls: 3 red, 4 white, and 3 blue.

You selected 2 balls at random. They may be

RR, WW, BB, RW, RB, WB, WR, BR, BW.

To find the probability of selecting the color of ball that you just selected, find this probability in each of previous cases:

RR: (One red ball left and 8 balls left in total)

$P_{RR}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}$

WW: (Two white balls left and 8 balls left in total)

$P_{WW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{2}{8}=\dfrac{1}{30}$

BB: (One blue ball left and 8 balls left in total)

$P_{BB}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}$

RW: (Two red and three white balls left and 8 balls left in total)

$P_{RW}=\dfrac{3}{10}\cdot \dfrac{4}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

RB: (Two red and two blue balls left and 8 balls left in total)

$P_{RB}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}$

WB: (Two blue and three white balls left and 8 balls left in total)

$P_{WB}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

WR: (Two red and three white balls left and 8 balls left in total)

$P_{WR}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

BR: (Two red and two blue balls left and 8 balls left in total)

$P_{BR}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}$

BW: (Two blue and three white balls left and 8 balls left in total)

$P_{BW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

In total, the probability of selecting the color of ball that you just selected is

$\dfrac{1}{120}+\dfrac{1}{30}+\dfrac{1}{120}+2\cdot\dfrac{1}{12}+2\cdot \dfrac{1}{20}+2\cdot \dfrac{1}{12}=\\ \\=\dfrac{1}{120}+\dfrac{4}{120}+\dfrac{1}{120}+\dfrac{20}{120}+\dfrac{12}{120}+\dfrac{20}{120}=\dfrac{58}{120}=\dfrac{29}{60}\approx 0.48$

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3 years ago

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