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BaLLatris [955]
2 years ago
5

I NEED HELP PLEASE HELP

Mathematics
2 answers:
Elanso [62]2 years ago
7 0

Answer:

66.) 1.) M=-9/7

2.) Y-INTERCEPT (9)

3.) X-INTERCEPT (7).

Crank2 years ago
6 0

Answer:

Step-by-step explanation:

I don’t really know, don’t answer falsely on my answer, I literally have a f^cking quiz

You might be interested in
Given the function below, find f(7) f(x)=-x^2+9x
sashaice [31]

Answer:

14

f(x) = 7

-7^2 + 9(7)= -49 + 63 = 14

3 0
3 years ago
A player of the National Basketball Association’s Portland Trail Blazers is the best free-throw shooter on the team, making 94%
g100num [7]

Answer:

The data for the probabilities are shown in the table below.

- A represents the probability of making the two shots for each of the best and worst shooter on the Portland Trail Blazers' team

- B represents the probability of making at least one shot for each of the best and worst shooter on the Portland Trail Blazers' team.

- C represents the probability of not making any of the two shots for each of the best and worst shooter on the Portland Trail Blazers' team.

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Step-by-step explanation:

Part 1

Probability of the best shooter of the National Basketball Association’s Portland Trail Blazers making a shot = P(B) = 94% = 0.94

Probability that he doesn't make a shot = P(B') = 1 - 0.94 = 0.06

a) Probability that the best shooter on the team makes the two shots awarded = P(B) × P(B) = 0.94 × 0.94 = 0.8836

b) Probability that the best shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(B) × P(B') + P(B') + P(B)

= (0.94 × 0.06) + (0.06 × 0.94) = 0.1128

Probability that he makes two shots = 0.8836 (already calculated in part a)

Probability that he makes at least one shot = 0.1128 + 0.8836 = 0.9964

c) Probability that the best shooter on the team makes none of the two shots = P(B') × P(B') = 0.06 × 0.06 = 0.0036

d) If the worst shooter on the team, whose success rate is 56% is now fouled to take the two shots.

Probability of the worst shooter on the team making a shot = P(W) = 56% = 0.56

Probability that the worst shooter on the team misses a shot = P(W') = 1 - 0.56 = 0.44

Part 2

a) Probability that the worst shooter on the team makes the two shots = P(W) × P(W)

= 0.56 × 0.56 = 0.3136

b) Probability that the worst shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(W) × P(W') + P(W') + P(W)

= (0.56 × 0.44) + (0.44 × 0.56) = 0.4928

Probability that he makes two shots = 0.3136 (already calculated in part a)

Probability that he makes at least one shot = 0.4928 + 0.3136 = 0.8064

c) Probability that the worst shooter makes none of the two shots = P(W') × P(W') = 0.06 × 0.06 = 0.1936

From the probabilities obtained

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Hope this Helps!!!

8 0
3 years ago
Read 2 more answers
Becca has saved 25% of the money that she needs to buy a new tennis racket. If she has saved $21 jow much money does the tennis
nexus9112 [7]
Let x be the entire portion of the money Becca needs to save to buy a new tennis racket.

So, 0.25x=$21

x=$21/0.25
x=$84

Thus, the total amount she needs to save is $84. Now, we'll deduct 25 from 84 to get the 75 percent or the remaining amount she has to save.

$84-$21=$63

The answer is $63.
6 0
3 years ago
Read 2 more answers
Consider a simple example of moral hazard. Suppose that Woodrow goes into a casino to make one bet a day. The casino is very bas
Neko [114]

Answer:

The expected value of the safe bet equal $0

Step-by-step explanation:

If  

S=\left\{s_1,s_2,...,s_n\right\}

is a finite numeric sample space and

P(X=s_k)=p_k for k=1, 2,..., n

is its probability distribution, then the expected value of the distribution is defined as

E(X)=s_1P(X=s_1)+s_2P(X=s_2)+...+s_nP(X=s_n)X)

What is the expected value of the safe bet?

In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is

S = {100,-100}

Since the coin is supposed to be fair,  

P(X=100)=0.5

P(X=-100)=0.5

and the expected value is

E(X) = 100*0.5 - 100*0.5 = 0

6 0
3 years ago
Salid bought 35 feet of window trim at a hardware store the trim cost 1.75 pet foot including sales tax if salid paid 100.00 bil
skad [1K]

Answer: Salid should get $38.75 of change.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Quantity of window trim bought: 35 feet </em>
  • <em>Cost per feet: $1.75 </em>
  • <em>Amount paid: $100 </em>

First, we have to calculate the total cost, by multiplying the Quantity of window trim bought (35) by the price per feet (1.75)

35 x 1.75 = $61.75

Finally, to calculate the change that Salid should get, we have to subtract the total cost (61.75) to the amount paid (100)

100-61.75=$38.75

6 0
2 years ago
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