6x+33-2(3x+1)
17+14
30+1
60-29
18+13
Subtract what is to the right of the equal sign form both side of the equation but any way the answer is 0
Answer:
80π
Step-by-step explanation:
Circle O with radius IO:
large radius = IO = 12 = R
Circle O with diameter JK
IJ = JK = KL = 2 × IO = 24
IJ = JK = KL = 24/3 = 8
small radius = 8/2 = 4 = r
The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.
That is the same as
1 semicircle of radius 12 plus 1 semicircle of radius 4
A = πR²/2 + πr²/2
A = π(12² + 4²)/2
A = 160π/2
A = 80π
Answer:
.
Step-by-step explanation:
All coterminal angles of an angle
are defined as
or 
where, n is an integer.
The given angle is

So, all coterminal angles of an angle
are

For n=1,




Since,
between 0 and 2π, therefore, the required coterminal angle is
.
Answer:
8, 10, 3
Step-by-step explanation:
For finding real solutions to cubic equations and those of higher degree, I find a graphing calculator to be useful. The problem can be cast in the form ...
f(x) = 0
where f(x) is the difference between the product of the integers and 240:
f(x) = x(x +2)(x -5) -240
Then all we need to do is ask the calculator to show the x-intercept. It is x=8.
So, the three integers are ...