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konstantin123 [22]
3 years ago
6

Which graph represents the parametric equations x = 1 – t2 and y = 2t, where 0 ≤ t ≤ 5?

Mathematics
2 answers:
skad [1K]3 years ago
6 0

Answer:

see image below

Step-by-step explanation:

OlgaM077 [116]3 years ago
3 0

Answer:

Graph A on Edge

Step-by-step explanation:

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Maryann's friends loved her bulletin board , and 4 of them asked her to make one for their homes. She offered to make each of he
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Complete Question:

To create a bulletin board, Maryann is planning to stretch fabric from burlap sacks over cardstock. She collects 6 kg of burlap sacks. The area density of the burlap is 0.4 kg/m².

Maryann's friends loved her bulletin board , and 4 of them asked her to make one for their homes. She offered to make each of her friends a replica of her bulletin board that measures 2 meters by 3 meters . How many kilograms of burlap should Maryann collect to complete the bulletin boards for her friends?

Answer:

To complete the bulletin boards for her friends, Maryanne should collect 6 kg of burlap more

Step-by-step explanation:

Mass of burlap sacks that Maryann collects = 6 kg

Area density of burlap = 0.4 kg/m²

Area Density = Mass / Area........(1)

The Area of bulletin board that can be made with the 6 kg of burlap sand can be calculated by using equation (1)

0.4 = 6 / Area

Area = 6/0.4

Area of bulletin board that can be made from 6 kg= 15 m² of bulletin board  

The area of bulletin board that Maryann made for herself = 2 * 3 = 6m²

To make similar bulletin boards for her four friends, the total area of bulletin board made for her 4 friends = 6 * 4 = 24m²

To calculate the mass of burlap required to make a 24m² bulletin board, use equation (1)

0.4 = Mass / 24

Mass = 0.4 * 24

Mass = 9.6 kg

The mass of burlap used to make Maryann's bulletin board alone:

0.4 = Mass/6

Mass = 2.4 kg

Out of the 6kg that she got, she has used 2.4 kg for herself

The remaining mass of burlap = 6 - 2.4 = 3.6 kg

Therefore, to complete the bulletin board for her friend, she should collect (9.6 - 3.6) = 6 kg of bulletin more

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