Question

A box contains 16 large marbles and 18 small marbles. Each marble is either green or white. 9 of the large marbles are green, and 3 of the small marbles are white. If a marble is randomly selected from the box, what is the probability that it is small or green

Answer 1

Answer:

$P(S&G) =0.7941$

Step-by-step explanation:

From the question we are told that:

Sample size $n=16+18=>34$

N0 of  Large $L=16$

N0 of Small $S=18$

N0 large Green $L_g=9$

N0 of small White $S_w=3$

Therefore

Number of green marbles $N0(G)=9+(18-3)$

Number of green marbles $N0(G)=24$

Generally the Number of both small and green Marble is

$N0 of (S&G)= 18 - 3 = 15$

Generally the  probability that it is small or green P(S&G) is mathematically given by

$P(S&G) = \frac{(18 + 24 - 15)}{(18 + 16)}$

$P(S&G) =0.7941$