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3 years ago

13

What is the slope in the linear equation y = 2x=1?

2 answers:

QveST [7]3 years ago

7 0

Answer:

its 2

comment for more understanding

Good luck

Bumek [7]3 years ago

5 0

Answer:

The slope of the line is 2

Step-by-step explanation:

y=2x+1, compare it to the slope intercept form of a line, y=mx+c, the slope will be 2

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What is -7+ 1/3.<br><br><br><br><br>pos helo

Nutka1998 [239]

Answer:

I'm not sure exactly what you mean but, here's my answer to 7 + 1/3.

22 /3

Step-by-step explanation:

5 0

3 years ago

A rectangular vegetable patch is 93 feet long and 37 feet wide. What is its area?

stealth61 [152]

Answer:

A= 3441

P = 260

Step-by-step explanation:

Area = l x w

93 x 37 = =3441

Perimeter = 2l + 2w

2(93) + 2(37) = 260

5 0

4 years ago

A phone company offers two monthly plans plan A cost $9 Plus And additional 0.12 $ for each minute of calls. Plan B cost $27 plu

Alisiya [41]

Answer: They will charge same amount for 360 minutes of calls.

Step-by-step explanation:

A phone company offers two monthly plans plan A cost $9 Plus And additional 0.12 $ for each minute of calls. Plan B cost $27 plus an additional $0.07 for each minute of calls

For what amount of calling do the two plans cost the same?

Let the each minute of calls be 'x'.

So, for plan A would be

plan A cost $9 Plus And additional 0.12 $ for each minute of calls is expressed as

$y_1=9+0.12x$

Plan B cost $27 plus an additional $0.07 for each minute of calls is expressed as

$y_2=27+0.07x$

According to question, it becomes,

$y_1=y_2\\\\9+0.12x=27+0.07x\\\\0.12x-0.07x=27-9\\\\0.05x=18\\\\x=\dfrac{18}{0.05}\\\\x=360$

Hence, they will charge same amount for 360 minutes of calls.

5 0

3 years ago

Which integer is 30 closest to

vesna_86 [32]

Answer:

7,4,15,6

Step-by-step explanation:

7,4,15,6

4 0

3 years ago

Read 2 more answers

Learning Task 3

ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. $Distance = 3682km$

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. $L < 38m$

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

$Perimeter = 160$

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

$Perimeter = x + x + 1 + x + 2 + x + 3$

This gives:

$160 = x + x + 1 + x + 2 + x + 3$

Collect Like Terms

$160 -1-2-3= x+x+x+x$

$154= 4x$

Divide both sides by 4

$38.5 = x$

$x =38.5$

<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>

<em></em>

Solving (b):

Given

Presently: $Inzo = 10 + Miz$

Five years ago: $Miz - 5= \frac{1}{3} * (Inzo-5)$ --- (Missing from the question)

Required: Determine their present ages

Substitute $10 + Miz$ for Inzo in the second equation

$Miz - 5 = \frac{1}{3} * (10 + Miz - 5)$

$Miz - 5 = \frac{1}{3} * (Miz + 5)$

Multiply both sides by 3

$3Miz - 15 = Miz + 5$

Collect Like Terms

$3Miz -Miz = 15 + 5$

$2Miz= 20$

Divide both sides by 2

$Miz = 10$

Substitute 10 for Miz in $Inzo = 10 + Miz$

$Inzo = 10 + 5$

$Inzo = 15$

<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>

Solving (3):

Given

Express Train:

$Speed = 100kph$

$Time = t$

Local Train:

$Speed = 45kph$

$Time = t + 45$

Required: Determine the distance between A and B

Distance is calculated as:

$Distance = Speed * Time$

For the express train:

$Distance = 100 * t$

For the local train

$Distance = 45 * (45 + t)$

Distance between both stations are equal; So,

$100 * t = 45 * (45 + t)$

$100 t = 2025 + 45t$

Collect Like Terms

$100 t -45t= 2025$

$55t= 2025$

Divide by 55

$t = 36.82$

Substitute 36.82 for t in $Distance = 100 * t$

$Distance = 100 * 36.82$

$Distance = 3682km$

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: $n + n + 2 > 24$

Sum less than 60: $n + n + 2 < 60$

So, we have:

$n + n + 2 > 24$

$2n + 2 > 24$

Collect Like Terms

$2n > 24-2$

$2n > 22$

$n > 11$

$n + n + 2 < 60$

$2n + 2< 60$

Collect Like Terms

$2n < 60-2$

$2n < 58$

Divide by 2

$n$

So, we have:

$n > 11$ and $n < 29$

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

$Perimeter < 152m$

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

$Perimeter =4 * L$

$Perimeter =4 L$

So, we have:

$4L < 152m$

Divide through by 4

$L < 38m$

Hence, length is less than 38m (e.g. 37m)

5 0

3 years ago