Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.´
<h3>¿Cuántas páginas se necesitarán para almacenar 517 tarjetas? </h3>
Sabemos que cada página puede almacenar hasta 9 cartas.
Entonces queremos ver cuantos grupos de 9 cartas hay en el conjunto de 517, para ver esto tomamos el cociente entre 517 y 9.
N = 517/9 = 57.44
Y no podemos tener un numero racional, así que debemos redondear al proximo número entero, que es 58.
Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.
Sí quieres aprender más sobre cocientes:
brainly.com/question/3493733
#SPJ1
Answer:
See explanation.
(Before continuing reading, I took the base to be 3. Please tell me if you didn't want the base to be 3.)
Step-by-step explanation:
I assume 3 is suppose to be the base. Let's list some values that can be written as 3 to some integer.
3^0=1
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
......
I could have also did negative integer powers, but this is all I really need to convince you that log_3(28) is between 3 and 4.
log_3(28) means the value x such that 3^x=28.
Since 28 is between 27 and 81 in my list above, that means 3^x is between 3^3 and 3^4. This means that x is a value between 3 and 4.
Idk this answer because no triangles are shaded.
Answer: the future value is $1748.4
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1550
r = 4% = 4/100 = 0.04
n = 365 because it was compounded 365 times in a year.
t = 3 years
Therefore,.
A = 1550(1 + 0.04/365)^365 × 3
A = 1550(1+0.00011)^1095
A = 1550(1.00011)^1095
A = 1550 × 1.128
A = 1748.4
