Cost of each pound of dog food = $2 .
Total cost of 9 pounds of dog food = 9 * 2 = $18.
Let us assume number of treats she can buy = t.
Cost of each treat = $1.
Cost of t number of treats = 1*t = 1t .
Total money Cara has = $25.
We can setup an inequality as,
Total cost of dog food + total cost of t number of treats ≤ 25.
18 + 1t ≤ 25.
Subtracting 18 from both sides, we get
18 + 1t -18 ≤ 25-18.
1t ≤ 7 or t ≤ 7.
So, she can purchase 7 or less treats.
13. 81.64
14. 803.84
15. 153.83
16. 753.6
you just use circumference and area formulas for a circle
Answer:
(a-6)(a+1)
Step-by-step explanation:
factor a2-5a-6
You got divide só see mean, the middle number is the median, range you add all number and divide but how many number has
Answer:
Greatest sack = 42
1 candy bar and 3 lollipops
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Step-by-step explanation:
Represent Candy bars with C and Lollipops with L
Solving (a): Greatest number of treat sacks
To solve this, we simply calculate the GCF of C and L
Hence, the GCF is
Hence, greatest number of sack is 42
Solving (b): Number of treat in each sack.
To do this, we simply divide the number of C and L by the calculated GCF
For C:
For L:
<em>Hence, 1 candy bar and 3 lollipops</em>
