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Marina86 [1]
3 years ago
5

Graph the following piecewise function and then find the range.

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0
C, [1,109). Hope this helps you m8
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Cara has $25 to buy dry pet food a pound of dog food costs $2 and treats are $1 apiece if she buys 9 pounds of food the greatest
zzz [600]

Cost of each pound of dog food = $2 .

Total cost of 9 pounds of dog food = 9 * 2 = $18.

Let us assume number of treats she can buy = t.

Cost of each treat = $1.

Cost of t number of treats = 1*t = 1t .

Total money Cara has = $25.

We can setup an inequality as,

Total cost of dog food + total cost of t number of treats ≤ 25.

18 + 1t ≤ 25.

Subtracting 18 from both sides, we get

18 + 1t -18  ≤ 25-18.

1t ≤ 7 or t ≤ 7.

So, she can purchase 7 or less treats.

5 0
2 years ago
Answer for any of these will help with work as well
Orlov [11]
13. 81.64
14. 803.84
15. 153.83
16. 753.6


you just use circumference and area formulas for a circle
8 0
3 years ago
Factor completely, then place the factors in the proper location on the grid. a2 - 5a - 6
horrorfan [7]

Answer:

(a-6)(a+1)

Step-by-step explanation:

factor a2-5a-6

7 0
3 years ago
The highway mileage (mpg) for a sample of 5 different models of a car company can be found below. Find
qaws [65]
You got divide só see mean, the middle number is the median, range you add all number and divide but how many number has
5 0
2 years ago
6. Steve is packing sacks for treats at a party. Every sack is exactly the same. Steve has 42 candy bars and 126 lollipops. a. W
Sergeu [11.5K]

Answer:

Greatest sack = 42

1 candy bar and 3 lollipops

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Step-by-step explanation:

Represent Candy bars with C and Lollipops with L

C = 42

L= 126

Solving (a): Greatest number of treat sacks

To solve this, we simply calculate the GCF of C and L

42 = 2^1 * 3^1 * 7^1

126 = 2^1 * 3^2 * 7^1

Hence, the GCF is

GCF = 2^1 * 3^1 * 7^1

GCF = 42

Hence, greatest number of sack is 42

Solving (b): Number of treat in each sack.

To do this, we simply divide the number of C and L by the calculated GCF

For C:

Treats = \frac{C}{GCF}

Treats = \frac{42}{42}

Treats = 1

For L:

Treats = \frac{L}{GCF}

Treats = \frac{126}{42}

Treats = 3

<em>Hence, 1 candy bar and 3 lollipops</em>

8 0
2 years ago
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