Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Answer:
the answer is 6.
Step-by-step explanation:
I think they want you to skip count down by 4 and there's your anwser.
Hope I helped.
SJ
The rate of change in z at (4,9) as we change x but hold y fixed is =
3/[2sqrt(3x+2y)] put x = 4 , y = 9 = 3/[2sqrt(12+18) = 3/[2sqrt(30)] The
rate of change in z at (4,9) as we change y but hold x fixed is =
1/sqrt(3x+2y) put x = 4, y =9 = 1/sqrt(30)
Answer:
33/7
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Discussion:
Given
64v^3 + 192v^2 - 56 v - 168
Factor 64v^2 from the first two terms. Factor 56 from the last two terms:
64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms
(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()
8(v+3)(8v^2-7) => factor 8y^2-7
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Thank you,
MrB
