Answer: x" = 5.69
Step-by-step explanation:
The graphic solution is attached.
Verifying the solution:
Existence condition: x > 0
2x - 4 = √x + 5
√x =2x - 4 - 5
√x =2x - 9 (²)
x = (2x - 9)²
x = 4x² - 36x + 81
4x² - 36x - x + 81 = 0
4x² - 37x + 81 = 0
Δ = -37² - 4.4.81 = 1369 - 1296 = 73
x = 37 ±√73/8
x' = 3.55
x" = 5.69
checking:
2*3.55 - 4 = 3.1
√3.55 + 5 = 6.88 Its not the same ∴ 3.55 is not a solution
2*5.69 - 4 = 7.39
√5.69 + 5 = 7.39 ∴ it's the only solution
Answer:
The answer is A)
Step-by-step explanation:
When the plane length increases, the force required gets reduced while the plane height stays the same.
<em>Hope this helps!</em>
Answer: 2 54
Step-by-step explanation:
Each shelf holds 8 trophies (2X4=8). 3 shelves times 8 trophies will equal a total of 24 trophies.
Answer:22.36 mi/hr
Step-by-step explanation:
Given
water in a river moves south at ![(V_w)10 mi/hr](https://tex.z-dn.net/?f=%28V_w%2910%20mi%2Fhr)
motorboat travels due to east at a speed of ![(V_b)20 mi/hr](https://tex.z-dn.net/?f=%28V_b%2920%20mi%2Fhr)
Velocity of boat relative to the moving water ![V_{bw}](https://tex.z-dn.net/?f=V_%7Bbw%7D)
![V_{bw}=V_b-V_w](https://tex.z-dn.net/?f=V_%7Bbw%7D%3DV_b-V_w)
![V_{bw}=20i-(-10j)=20i+10j](https://tex.z-dn.net/?f=V_%7Bbw%7D%3D20i-%28-10j%29%3D20i%2B10j)
Magnitude of ![V_{bw}=\sqrt{20^2+10^2}=\sqrt{500}](https://tex.z-dn.net/?f=V_%7Bbw%7D%3D%5Csqrt%7B20%5E2%2B10%5E2%7D%3D%5Csqrt%7B500%7D)
![V_{bw}=10\sqrt{5} \approx 22.36 mi/hr](https://tex.z-dn.net/?f=V_%7Bbw%7D%3D10%5Csqrt%7B5%7D%20%5Capprox%2022.36%20mi%2Fhr)
![tan\theta =\frac{10}{20}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7B10%7D%7B20%7D)
with the x axis.