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natta225 [31]
2 years ago
14

List safety conditions when downloading shareware, free free where, or public domain software

Computers and Technology
1 answer:
Anit [1.1K]2 years ago
6 0

Answer:

Explanation:

Freeware and shareware programs are softwares which are either free of charge or consist of a free version for a certain trial period. These programs pose a threat of habouring malware or viruses which could damage one's computer and important files and programs. Therefore, it is imperative that carefulness is maintained when trying to get these softwares.

Some of the necessary safety conditions that should be taken include;

1) Appropriate research about the software including taking more about the vendors and reviews.

2.) Once, a healthy review has been identified ; the download can begin with the Downloader ensuring that the download is from the recommended site.

3) Prior to installation the software should be scanned with an active anti-virus program to determine if there is possibility that a virus has creeped in.

4.) Some softwares may require that computer anti-virus be turned off during installation, this is not always a good idea as this act leaves the system vulnerable a d badly exposed.

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Implement a Java program that creates math flashcards for elementary grade students. User will enter his/her name, the type (+,
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import java.util.Scanner;

public class JavaApplication44 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.print("Enter you name: ");

       String name = scan.nextLine();

       System.out.print("Enter your operation (+,-,*,/): ");

       String operator = scan.nextLine();

       System.out.print("Enter the range of the problems: ");

       int ran = scan.nextInt();

       System.out.print("Enter number of problems: ");

       int problems = scan.nextInt();

       int score = 0;

       for (int i = 1; i <= ran; i++){

           int first = (int)(Math.random()*ran);

           int sec = (int)(Math.random()*ran);

           System.out.print("Problem #"+i+": "+first + " "+operator+" "+sec+" = ");

           int ans = scan.nextInt();

           if (operator.equals("+")){

               if (ans == first + sec){

                   System.out.println("Correct!");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first+sec));

               }

           }

           else if(operator.equals("-")){

               if (ans == first - sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first - sec));

               }

           }

           else if (operator.equals("*")){

               if (ans == first * sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first * sec));

               }

           }

           else if (operator.equals("/")){

               if (ans == first / sec){

                   System.out.println("Correct");

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               }

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                   System.out.println("Wrong. The correct answer is "+(first / sec));

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}

I hope this helps!

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Answer:

C) public domain

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