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V125BC [204]
3 years ago
10

A lottery ticket contains five unique numbers. A set of unique numbers does not contain repeated elements. The winning combinati

on of this lottery is chosen by picking five unique numbers. Define a function matches(ticket, winners) that takes two lists and returns an integer that says how many numbers the two lists have in common.
Computers and Technology
1 answer:
RSB [31]3 years ago
6 0

Answer:

Answer explained below

Explanation:

I have given two approaches in implementing the solution.

1. Using the for loop, in which you have to iterate over all the elements in list 1 and check in list 2

2. Use the set intersection method. As intersection will give u the common elements. And we can get there length by using len method.

I have added the code along with the snapshot and inline comment for the ease of you to understand. Please check the methods below. You can use either of them.

METHOD-1:

********** CODE *****************

def matches(tickets,winner):

tickets = set(tickets)

winner = set(winner)

counter = 0 #To Count the common elements

for i in tickets: # Iterate over all the elements in tickets.

if i in winner: # Check the element in the winner list

counter = counter+1

return counter

METHOD -2:

********** CODE ********************

def matches(tickets, winner):

tickets = set(tickets)

winner = set(winner)

return len(tickets.intersection(winner))

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Answer:

Following are the code to this question:

def binarynumber(num):#defining a method binarynumber that accepts a parameter num

   x=""#defining a string variable x

   if (num!=0):#defining if condition to check number not equal to 0

       while (num>=1):#defining a loop that check value is grater then equal to one

           if (num %2==0):#defining if condition to check num is even

               x=x+"0" #add string value 0 in num variable

               num=num/2 #divide the value by 2

           else:#defining else block

               x=x+"1"#add string value 1 in num variable

               num=(num-1)/2#first subtract 1 into num variable then divide the value by 2

   else:

       x="0"#assign string value 0 in num variable  

   return "".join(reversed(x))#return value

num = int (input ("Enter any number: "))#defining num variable that input the integer value

print (binarynumber(num))#using print method to call method binarynumber with passing num parameter

Output:

Enter any number: 12

1100

Explanation:

  • In the above python code a method "binarynumber" is declared, in which the "num" variable passes as the parameter inside the method a string variable "x" is declared that stores all converted values.
  • Inside the method and if the block is declared that checks number value is not equal to 0 if this condition is false then it will add string value and reverse its value.
  • Or if the condition is true it defines a while loop that calculates the given number binary digits and returns its value.
  • At the last step, the num variable is declared that inputs the integer value from the user end and calls the method by using the print method.    
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Explanation:

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3 years ago
7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f
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Answer:

Here is the CoordTransform() function:              

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2; }

The above method has four parameters xVal  and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *

Here new variables are xValNew  and yValNew and old is represented by xVal and yVal.

Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.

Explanation:

Here is the complete program:

#include <iostream>

using namespace std;

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2;}

int main()

{ int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser;

cin >> yValUser;

CoordTransform(xValUser, yValUser, xValNew, yValNew);

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;

return 0; }

The output is given in the attached screenshot   

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3 years ago
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