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drek231 [11]
3 years ago
11

Which number is composite 5,2,9,11

Mathematics
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

9 number is composite is answer

Step-by-step explanation:

1,3,9 can be exactly divided by

I hope this is helpful!

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Where L is the length, in feet, of the pendulum, and π is approximately 22/7. How long must the pendulum be if one complete cycl
vaieri [72.5K]

Answer:

The simple pendulum should be 15.9 m long.

Step-by-step explanation:

Approximately (for small amplitudes), the period of a simple pendulum is

T = 2*pi * sqrt (L/g), L=length

using pi = 22/7, and g=9.8 m/s^2

8 = 2* 22/7 * sqrt(L/9.8)

solve for L

L = (8*7/(2*22))^2 * 9.8

= 15.874 m

That's quite a long pendulum!

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3 years ago
Triangle A B C is cut by line segment M N. Line segment M N goes from side A B to side B C and cuts both sides into equal parts.
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Answer: A.) 58 cm

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3 years ago
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X = y^2 - 1
ohaa [14]

Answer:  The correct option is (B) 2y^2-y-6=0.

Step-by-step explanation:  We are given the following system of equations :

x=y^2-1~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\2x-y=4~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

We are to find the equation that could be the result of using substitution to solve the above system.

Substituting the value of x from equation (i) in equation (ii), we get

2x-y=4\\\\\Rightarrow 2(y^2-1)-y=4\\\\\Rightarrow 2y^2-2-y=4\\\\\Rightarrow 2y^2-y-2-4=0\\\\\Rightarrow 2y^2-y-6=0.

Thus, the required equation is 2y^2-y-6=0.

Option (B) is CORRECT.

5 0
3 years ago
The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure
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Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?  

Use 3.14 to approximate π .  


Enter your answer in the box.  in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cylinder volume)

V = \pi *r^2*h

V = 3.14 *2.5^2*7

V = 3.14*6.25*7

V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{2.5^3}{3}

V = 2*3.14 * \dfrac{15.625}{3}

V = \dfrac{98.125}{3}

\boxed{ V_{hemisphere} \approx 32.70\:in^3}

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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To graph this situation we must take into account the data and the organization of each of them on the X axis and Y axis.

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To graph this situation we must take into account the data we have:

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