Lets say that J is for Jennys messages, B is for Boris’ and E is for Erics (or Ericas?).
79 = J + B + E
J = E - 6
B = 3E
Since both Jenny’s and Boris’ number of text messages has some kind of relation to Eric’s number of messages, we can say that:
79 = E - 6 (Jenny) + 3E (Boris) + E (Eric), so:
79 = E - 6 + 3E + E /combine like terms
79 = 5E - 6 /add 6 to both sides
79 + 6 = 5E /switch sides + combine like terms
5E = 85 /divide both sides by 5
E = 85/5
E = 17
So, Eric sent 17 messages. Lets get back to those equations we made for Jenny and Boris:
J = E - 6 = 17 - 6 = 11
B = 3E = 3 * 17 = 51
And we can check if it adds up: 51 + 11 + 17 = 79, which is what we were supposed to get.
<h3>Answer:</h3>
1165.83 kg
<h3>Explanation:</h3>
The total mass is the product of volume of one brick, the number of bricks, and the density. For this problem, it is convenient to use dimensions in meters.
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