5Cblue%7Bl%7D%20%20%5Chuge%5Cmathfrak%5Cred%7Bv%7D%20%20%5Chuge%5Cmathfrak%5Cgreen%7Be%7D%20%5Chuge%5Cmathfrak%5Corange%7B%E2%9E%94%7D%5C%20%20" id="TexFormula1" title=" \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{v} \huge\mathfrak\green{e} \huge\mathfrak\orange{➔}\ " alt=" \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{v} \huge\mathfrak\green{e} \huge\mathfrak\orange{➔}\ " align="absmiddle" class="latex-formula">
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The second equation gives
This leaves us with
where
Hence the maximum possible area is 2500 square meteres
Given the area of the rectangular garden expressed as;
The maximum area occurs when dA(x)/dx = 0
Next is to get the maximum area possible. Substitute x = 50 into the original function as shown;
Hence the maximum possible area is 2500 square meters