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3 years ago

Can an isosceles triangle be a right angle

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Yes. An isosceles can be a right triangle.

Because an isosceles triangle has two equal angles, two can be 45, and one can be 90.

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Given the function f(x) =

jenyasd209 [6]

Answer:

The value of f(1) is smaller than the value of f(3)

Step-by-step explanation:

<u><em>The correct question is</em></u>

Given the function f(x) = 2x^2 + 3x + 10, find f(1) and f(3). Choose the statement that is true concerning these two values.

The value of f(1) is the same as the value of f(3).

The value of f(1) cannot be compared to the value of f(3).

The value of f(1) is larger than the value of f(3).

The value of f(1) is smaller than the value of f(3)

we have

$f(x)=2x^{2}+3x+10$

step 1

Find out the value of f(1)

substitute the value of x=1 in the function f(x)

For x=1

$f(1)=2(1)^{2}+3(1)+10$

$f(1)=15$

step 2

Find out the value of f(3)

substitute the value of x=3 in the function f(x)

For x=3

$f(3)=2(3)^{2}+3(3)+10$

$f(3)=37$

step 3

Compare the values

37> 15

f(3) > f(1)

f(1) < f(3)

therefore

The value of f(1) is smaller than the value of f(3)

8 0

3 years ago

Please help with the mathematical questions

ki77a [65]

Answer:

se"x cha"t with me boys insta id 123bhi__

8 0

2 years ago

Read 2 more answers

Assume that 3 digits are selected at random from the set {1,3,5,6,7,8} { 1 , 3 , 5 , 6 , 7 , 8 } and are arranged in random orde

Mumz [18]

Sample space is 36.so the probability must be 20/36.from three digits the maximum no.of number can be made is 6.

4 0

3 years ago

The radius of a right circular cone is increasing at a rate of 1.5 in/s while its height is decreasing at a rate of 2.1 in/s. At

givi [52]

Answer:

The volume of the cone is changing at a rate of approximately 8670.796 cubic inches per second.

Step-by-step explanation:

Geometrically speaking, the volume of the right circular cone ( $V$ ), in cubic inches, is defined by the following formula:

$V = \frac{1}{3}\cdot \pi \cdot r^{2}\cdot h$ (1)

Where:

$r$ - Radius, in inches.

$h$ - Height, in inches.

Then, we derive an expression for the rate of change of the volume ( $\dot V$ ), in cubic inches per second, by derivatives:

$\dot V = \frac{1}{3}\cdot \pi \cdot (2\cdot r\cdot h \cdot \dot r + r^{2}\cdot \dot h)$ (2)

Where:

$\dot r$ - Rate of change of the radius, in inches per second.

$\dot h$ - Rate of change of the height, in inches per second.

If we know that $r = 120\,in$ , $\dot r = 1.5\,\frac{in}{s}$ , $h = 107\,in$ and $\dot h = -2.1\,\frac{in}{s}$ , then the rate of change of the volume is:

$\dot V \approx 8670.796\,\frac{in^{3}}{s}$

The volume of the cone is changing at a rate of approximately 8670.796 cubic inches per second.

8 0

3 years ago

Solve: 1/2log81/17 + 2log5/3 - log17/4 + 3/2log17

goldenfox [79]

2log10(3) 2log10(5) 5log10(17)
_______ + _______ + _________
17 3 4

=2.06017

8 0

3 years ago