Answer:
1. 516 ppm; 2. 561 ppm
Step-by-step explanation:
1. CO₂ increase at old rate
Time = 2100 - 2010 = 90 years
Increase in CO₂ = 90 yr × (1.4 ppm/1 yr) = 126 ppm
CO₂ in 2010 = 390 + 126 = 516 ppm
At the old rate, the CO₂ concentration in 2100 will be 516 ppm.
2. CO₂ increase at new rate
Time = 2100 - 2010 = 90 years
Increase in CO₂ = 90 yr × (1.9 ppm/1 yr) = 171 ppm
CO₂ in 2010 = 390 + 171 = 561 ppm
At the new rate, the CO₂ concentration in 2100 will be 561 ppm.
Because it specialises the groups that go into the number.
Answer: Choice D
(a-e)/f
=======================================
Explanation:
Points D and B are at locations (e,f) and (a,0) respectively.
Find the slope of line DB to get
m = (y2-y1)/(x2-x1)
m = (0-f)/(a-e)
m = -f/(a-e)
This is the slope of line DB. We want the perpendicular slope to this line. So we'll flip the fraction to get -(a-e)/f and then flip the sign from negative to positive. That leads to the final answer (a-e)/f.
Another example would be an original slope of -2/5 has a perpendicular slope of 5/2. Notice how the two slopes -2/5 and 5/2 multiply to -1. This is true of any pair of perpendicular lines where neither line is vertical.
Answer:
The numbers
such that the average value of
on the interval [0, b] is equal to 8 are
and
.
Step-by-step explanation:
The mean value of function within a given interval is given by the following integral:

If
,
,
and
, then:





The roots of this polynomial are determined by the Quadratic Formula:
and
.
The numbers
such that the average value of
on the interval [0, b] is equal to 8 are
and
.
Answer:
Option B
y coordinate is 0
Step-by-step explanation:
We have in two dimension rectangular system of coordinates with two mutually perpendicular lines called x and y axis.
X axis is the horizontal line and y the vertical line, the point of intersection of these two lines is called origin with x=0: y=0
To the right of origin, positive values are marked and left negative. Similarly for y axis, above origin positive values and below negative values.
Thus we have along x axis, y values to be 0
Hence any point on x coordinate will be of the form (a,0) where a can be any real number
So option B is right