Answer:

is the required relation of the diameter of an orange at the 67th percentile compare with the mean diameter.
Step-by-step explanation:
We are given the following information in the question:
Standard Deviation, σ = 0.3 inch
We are given that the distribution of diameters is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.67.
Calculation the value from standard normal z table, we have,

which is the required relation of the diameter of an orange at the 67th percentile compare with the mean diameter.
I think the answer is x=-1
The fifth root of 32 is 2
In other words,
![\sqrt[5]{32} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B32%7D%20%3D%202)
It's similar to stating that 7^2 = 49 can be transformed into saying sqrt(49) = 7 where "sqrt" is shorthand for "square root"
The general rule is
![x^n = b \ \ \longleftrightarrow \ \ \sqrt[n]{b} = x](https://tex.z-dn.net/?f=x%5En%20%3D%20b%20%5C%20%5C%20%20%5Clongleftrightarrow%20%5C%20%5C%20%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20x)
Answer:
Step-by-step explanation:
-1/6-(-9/10)
=-1/6+9/10
