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3 years ago

Write 74 in expanded form. Then check all that apply.

Mathematics

1 answer:

ASHA 777 [7]3 years ago

7 0

Answer:

7x7x7x7

Step-by-step explanation:

The exponent is 4. The exponent tells you to multiply 7 together 4 times

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the rule for being the nth item in a certain sequence is n(n+1)/2. what is the 4th term in this sequence ? a.) 4b.)10c.)16d.)20

abruzzese [7]

The 4th term of the sequence can be determined as,

$\begin{gathered} a_n=\frac{n(n+1)}{2} \\ a_4=\frac{4(4+1)}{2} \\ a_4=10 \end{gathered}$

Thus, option (b) is correct.

3 0

1 year ago

X^3-13x^2+40x=0 quadratic

777dan777 [17]

Answer:

x(x-5)(x-8)

x=5

x=8

Step-by-step explanation:

x(x^2-13x+40)

x(x-5) (x-8)

6 0

3 years ago

You rent an apartment that costs $900 per month during the first year, but the rent is

olchik [2.2K]

Answer:1493.1

Step-by-step explanation:

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2 years ago

Read 2 more answers

PLEASE PLEASE HELP!!! Match each pair of matrices with its product matrix.

Butoxors [25]

Answer:

Step-by-step explanation:

Did the calculations myself, probably too late for these to be of any use but I'll leaave them here anyways for anyone else that needs it in the future. Love yall!

4 0

3 years ago

A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w

AfilCa [17]

Answer:

$\frac{15}{4802}$ , $\frac{15}{9604}$ , $\frac{9}{2401}$ , $\frac{9}{4802}$

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: $\frac{4}{14}$

green: $\frac{2}{14}$

yellow: $\frac{3}{14}$

blue: $\frac{5}{14}$

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = $\frac{3}{14} \cdot \frac{4}{14} \cdot \frac{2}{14} \cdot \frac{5}{14} =\frac{15}{4802}$

Removing 1 blue, 1 green, 1 green, and 1 yellow = $\frac{5}{14} \cdot \frac{2}{14} \cdot \frac{2}{14} \cdot \frac{3}{14} =\frac{15}{9604}$

Removing 1 red, 1 red, 1 yellow, and 1 yellow = $\frac{4}{14} \cdot \frac{4}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} =\frac{9}{2401}$

Removing 1 green, 1 yellow, 1 yellow, and 1 red = $\frac{2}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} \cdot \frac{4}{14} =\frac{9}{4802}$

4 0

2 years ago