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kow [346]
3 years ago
11

Solve the equation for a. K=4a+9ab

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

a= k/4+9b

Step-by-step explanation:

hope this helps, if not let me know!

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Please answer this question!! 30 points and brainliest!
Alexeev081 [22]

2x(-5x-3)

2x(-5x)= -10x    and 2x(-3)= -6x

= -10x sq - 6x

-10x is sq bc you are multiplying the same variable twice


5 0
3 years ago
Ash buys 5 bunches of flowers. Each bunch contains 10 flowers. He gets 8 more flowers from his yard.
Semenov [28]

Answer:

5 x 10 + 8 = f

Step-by-step explanation:

The reason it is 5 x 10 + 8 = f, is because each bunch has 10 and Ash has five.

In order to find how many flowers he has in 5 bunches is to multiply by how many flowers each bunch has.

Then he gets 8 more flowers which is why it has +8 in the equation.

6 0
2 years ago
Read 2 more answers
I need help remembering the steps too solve 6x +9 =12
svp [43]

Answer:

x= 1/2

Step-by-step explanation:

6x+9=12

Step 1: Subtract 9 from both sides.

6x+9−9=12−9

6x=3

Step 2: Divide both sides by 6.

6x/6= 3 /6

And Your Answer Will Be:

x= 1/2

3 0
4 years ago
Speed, Time, and Dis
serious [3.7K]

Answer:

3 hours

Step-by-step explanation:

Recall:

Distance = speed x time

we are given that speed = 18 km/h and distance = 54 km.

hence,

54 = 18 x time   (divide both sides by 18 and rearrange)

time = 54/18 = 3 hours

7 0
3 years ago
Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.
Keith_Richards [23]
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0
3 years ago
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