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pychu [463]
3 years ago
13

Solve 148×35. using us standard algorithm

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0
It would be 5180 for the answer
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A bottle holds 540 milliliter a of liquid. How much is this in ounces? Use the following conversion: 1punce is30 milliliter
kaheart [24]
540mL/30mL=18 ounces
5 0
3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
What strategy for finding area and perimeter of a 2 dimensional shape?
Mice21 [21]
Area is supposed to be multiplied by 2.
8 0
3 years ago
Read 2 more answers
What’s the slope of -2,2 and 4,-10
uysha [10]
Slope formula: y2-y1/x2-x1
-10-2/4-(-2)
-12/6
-2
The answer is -2
7 0
3 years ago
2/7 x (-3/8) i need the answer
SOVA2 [1]
Multiply top by top
2 * -3 = -6
Multiply bottom
7 * 8 = 56
The answer is -6/56
Simplify = -3/28
8 0
3 years ago
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