Answer:
def UpdateScore(score, total):
if total % 2:
print total, "is odd, so adding 10"
score += 10
else:
print total, "is even, so subtracting 5"
score -= 5
print "The score is now",score
return score
score = 0
score = UpdateScore(score, 3)
score = UpdateScore(score, 6)
Explanation:
The % operator returns the remainder after division. So if you divide by 2, the remainder is either 0 or 1, where 0 indicates an even number, and 1 indicates an odd number. The above program shows that.
Answer:
B. Computer Repair
Explanation:
I got it right on edge. trust.
I believe it is That product is sustainable.
lst=([])
def avgGPA(lst1):
total = 0
count = 0
for x in lst:
if type(x) == int:
total += x
count += 1
return total/count
def GPAcalc(grade, weighted):
grade = grade.lower()
dictionary = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}
if weighted == 1 and grade in dictionary:
lst.append(dictionary[grade]+1)
return "Your GPA score is: " + str(dictionary[grade] + 1)
elif weighted == 0 and grade in dictionary:
lst.append(dictionary[grade])
return "Your GPA score is: " + str(dictionary[grade])
else:
lst.append("Invalid")
return "Invalid"
classes = int(input("How many Classes are you taking? "))
i = 0
while i < classes:
print(GPAcalc(input("Enter your Letter Grade: "), int(input("Is it weighted? (1 = yes) "))))
i += 1
print("Your weighted GPA is a "+str(avgGPA(lst)))
If you need me to change any code, I'll do my best. I hope this helps!
Answer:
4)true
5)no(not good for computer )
6)easy
