Wipe off the hard drive with a software eraser but it won't be quick and won't work on defective disks
Answer:
The correct answer to the following question is option "b".
Explanation:
The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).
- In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
- In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".
That's why the option "b" is correct.
Answer:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
int[] array = new int[10];
int index = 0;
while(index < array.size()){
int number = (rand() % 100) + 1;
for (int i = 0; i < 1; i++) {
array[index] = number;
cout<< "Position "<< index << "of the array = "<< number << endl;
++index;
}
}
}
Explanation:
The while loop in the source code loops over a set of code ten times, The for loop only loops once to add the generated random number between 1 and 100 to the array of size 10. At the end of the for loop, the index location and the item of the array is printed out on the screen. The random number is generated from the 'rand()' function of the C++ standard library.
Answer:
When the driver is <em>reversing the car</em>
Explanation:
The Rear Cross Traffic Alert (RCTA) is Nissan's <em>risk of collision detector</em> that warns drivers if one or more cars are approaching the rear of your car when backing up from a parking space.
Sensors around the back of the vehicle identify vehicles drawing nearer from the either way. A notice tone and glimmering light will appear and alert the driver to stop.
