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Step-by-step explanation:
Point slope form: (y−y1) = m (x−x1), where (x1,y1) is the point, and m is the slope.
(y- (-4)) = (5/6)*(x - 8)
(y + 4) = (5/6)*(x - 8)
If you want in standard form
(y + 4) = (5/6)*x - (5/6)*8
y = (5/6) x - (5/6)*8 - 4
y = (5/6)x - (16/6)
Answer:
(y + 4) = (5/6)*(x - 8)
Answer:
Is this a question. If so I will change my answer
Step-by-step explanation:
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
16 because it’s basic multiplication
On a coordinate plane, a curve crosses the y- axis at (0,1). It has a minimum of negative 1 and a maximum of 1. It goes through 2 cycle at 2 pi.
