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2 years ago

Math question right here

Mathematics

2 answers:

MariettaO [177]2 years ago

6 0

Answer: I think its BC and DC I dont know But I hope this helps!

Step-by-step explanation:

Orlov [11]2 years ago

5 0

Answer:

∠ACB ≅ ∠ACD

Step-by-step explanation:

The SAS Postulate tells us:

If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

(Congruent = exactly the same)

(included angle is formed by the two known sides)

In this example we can see that 2 sides are congruent (by the dashes on the lines and the fact that both triangles share side AC), but we do not know if the included angles are congruent.

Therefore, we need to know if ∠ACB ≅ ∠ACD

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alexdok [17]

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4 years ago

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4 years ago

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3 years ago

Read 2 more answers

In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of

Gwar [14]

We can use the Сosine formula to solve this problem.
First we must find the third side (АС) of the triangle:

$AC^2=AB^2+BC^2-2*AB*BC*cos82^o \\ AC^2=8^2+11^2-2*8*11*0.1392 \\ AC^2=64+121-24.4992= 160.508 \\ AC= \sqrt{160.508} \approx 12.67 \ cm$

The smallest angle of the triangle lies opposite the smallest side, so we need to find m∠C.

$cosC= \frac{AC^2+BC^2-AB^2}{2*AC*BC} \\ \\ cosC= \frac{12.67^2+11^2-8^2}{2*12.67*11}= \frac{160.53+121-64}{278.74} = \frac{217.53}{278.74} \approx 0.7804$

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

Answer: 38.7°

I hope this helps

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4 years ago

the hypotenuse of a right leg triangle is 12 centimeters, and the shorter leg is 6 centimeters. Find the length of the other leg

ankoles [38]

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