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hoa [83]
3 years ago
13

A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the

rectangle becomes 35.28 cm2. Calculate the length of the longer of the two sides of the initial rectangle.
Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0

Answer: 5.7\ cm

Step-by-step explanation:

Given

Rectangle has an area of 19.38\ cm^2

Suppose rectangle length and width are l and w

If each side is increased by 1.50\ cm

Area becomes A_2=35.28\ cm^2

We can write

\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)

Substitute the value of width from (ii) in equation (i)

\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7

Width corresponding to these lengths

w=5.7,\ 3.4

Therfore, we can write the length of the longer side is 5.7\ cm

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